在SQL SERVER2005中实现素数计算
类别: 数据库教程
我将提出一个挑战,谁能用SQLSEERVER提出计算素数最好的方法,
我用了一个新的特点CTE和某些TSQL实现,但均不理想,前者(CTE)有限制,而后者(TSQL)产生一百万个素数用了7分种
你可以干的更好么?
这儿是我的一些代码段落
(TSQL实现)
set nocount on
declare @prime table (prime int not null primary key)
--insert into @prime values (2)
--insert into @prime values (3)
--insert into @prime values (5)
--insert into @prime values (7)
--insert into @prime values (11)
declare @number int, @pc int
set @number = 13
set @pc = 1
while @pc < 1000000
begin
if not exists (select 1 from @prime where @number % prime = 0 and prime < sqrt(@number) )
begin
insert into @prime select @number
set @pc = @pc +1
end
set @number = @number
+ case when @number %2 = 1 then 2
when @number %3 = 2 then 2
when @number %5 = 4 then 2
when @number %7 = 6 then 2
when @number %11 = 10 then 2
else 1 end
end
select @pc
和
(CTE实现)
with seq
as( select 13 number
union all
select s.number
+ case when s.number %2 = 1 then 2
when s.number %3 = 2 then 2
when s.number %5 = 4 then 2
when s.number %7 = 6 then 2
when s.number %11 = 10 then 2
else 1 end
from seq s
where number < 32767
)
, prime as (
select s.number
from seq s
where not exists ( select 1 from seq s2 where s2.number < s.number and (s.number) % s2.number = 0)
)
select *
from prime
option (MAXRECURSION 32767)
我用了一个新的特点CTE和某些TSQL实现,但均不理想,前者(CTE)有限制,而后者(TSQL)产生一百万个素数用了7分种
你可以干的更好么?
这儿是我的一些代码段落
(TSQL实现)
set nocount on
declare @prime table (prime int not null primary key)
--insert into @prime values (2)
--insert into @prime values (3)
--insert into @prime values (5)
--insert into @prime values (7)
--insert into @prime values (11)
declare @number int, @pc int
set @number = 13
set @pc = 1
while @pc < 1000000
begin
if not exists (select 1 from @prime where @number % prime = 0 and prime < sqrt(@number) )
begin
insert into @prime select @number
set @pc = @pc +1
end
set @number = @number
+ case when @number %2 = 1 then 2
when @number %3 = 2 then 2
when @number %5 = 4 then 2
when @number %7 = 6 then 2
when @number %11 = 10 then 2
else 1 end
end
select @pc
和
(CTE实现)
with seq
as( select 13 number
union all
select s.number
+ case when s.number %2 = 1 then 2
when s.number %3 = 2 then 2
when s.number %5 = 4 then 2
when s.number %7 = 6 then 2
when s.number %11 = 10 then 2
else 1 end
from seq s
where number < 32767
)
, prime as (
select s.number
from seq s
where not exists ( select 1 from seq s2 where s2.number < s.number and (s.number) % s2.number = 0)
)
select *
from prime
option (MAXRECURSION 32767)
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